ACSL STRING

ACSL STRING

Question


My thought


Nothing… The problem is pretty easy, however it troubled me for a quite long time. Just follow the instruction of the problem and simulate the whole process by coding.

Points to note


  • The conversion between String and int
  • How to handle carry
  • Pay attention to the additional sign
  • Sometimes we can use char to simplify the process

Code


1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
import java.util.Scanner;
class test
{
static String num1;
static int num2,num3;
public static void input()
{
Scanner input = new Scanner(System.in);
String s = input.next();
int len = s.length();
for(int i=0;i<len;i++)
{
if(s.charAt(i)==',')
{
num1 = s.substring(0,i);
num2 = s.charAt(i+1)-'0';
num3 = s.charAt(i+3)-'0';
break;
}
}
input.close();
// System.out.println(num1);
// System.out.println(num2);
// System.out.println(num3);
}

public static void noSolution(int decimalPoint)
{
int IntgerNum = num2 - num3 - 1;
while((IntgerNum--)!=0)
{
System.out.print("#");
}
System.out.print(".");
for(int i=0;i<num3;i++)
{
System.out.print("#");
}
}

public static void process()
{
//find the decimal point
int decimalPoint = num1.indexOf(".");
int decimalLength = num1.length() - decimalPoint - 1;
int integerLength = decimalPoint;

//find the impossible situation
if(decimalLength < num3 ||integerLength + 1 + num3 > num2)
{
noSolution(decimalPoint);
return;
}

String newNum = num1.substring(0,decimalPoint+num3+1);

// System.out.println(newNum);

//convert to integer
String tmp="";
int newLen = newNum.length();
for(int i=0;i<newLen;i++)
{
if(newNum.charAt(i)=='.') continue;
tmp += newNum.substring(i,i+1);
}

int haveASign = 0;
if(tmp.charAt(0)=='+')
{
haveASign = 1;
tmp = tmp.substring(1);
}
else if(tmp.charAt(0)=='-')
{
haveASign = -1;
tmp = tmp.substring(1);
}

// System.out.print(tmp);
int intTmp = Integer.valueOf(tmp);
//carry
if(newLen+1<=num1.length() && num1.charAt(newLen)>'4') intTmp++;

String stringTmp = Integer.toString(intTmp);

int nowLength = stringTmp.length() + 1 + Math.abs(haveASign);

int cntOutput = 0;
for(int i=0;i<num2-nowLength;i++)
{
System.out.print("#");
cntOutput++;
}
if(haveASign==-1)
{
System.out.print("-");
cntOutput++;
}
else if(haveASign==1)
{
System.out.print("+");
cntOutput++;
}
//print integer
int p=0;
for(p=0;p<num2-1-cntOutput-num3;p++)
{
System.out.print(stringTmp.charAt(p));
}
System.out.print(".");
for(;p<stringTmp.length();p++)
{
System.out.print(stringTmp.charAt(p));
}

}
public static void main(String[] args)
{
input();
process();
}
}

Tips


String.split(String)

This method can be used to split a string into parts following the instruction.

  • When use . or | as the symbol of split position, we need to use Escapes //.

  • It returns a array with the satisfied arrays

Author

Haojin Li

Posted on

12-01-2019

Updated on

03-05-2022

Licensed under

Comments